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The perimeter of a rectangle is 25.5 m. ...

The perimeter of a rectangle is 25.5 m. Its length is 9.5 m. Calculate its area in sq. m `(m^(2))`.

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To solve the problem step by step, we will follow the process outlined in the video transcript: ### Step 1: Understand the given information We are given: - Perimeter of the rectangle (P) = 25.5 m - Length of the rectangle (L) = 9.5 m ### Step 2: Use the formula for the perimeter of a rectangle The formula for the perimeter (P) of a rectangle is given by: \[ P = 2(L + B) \] where \( B \) is the breadth of the rectangle. ### Step 3: Substitute the known values into the perimeter formula Substituting the known values into the perimeter formula: \[ 25.5 = 2(9.5 + B) \] ### Step 4: Simplify the equation To isolate \( B \), first divide both sides by 2: \[ 9.5 + B = \frac{25.5}{2} \] Calculating the right side: \[ 9.5 + B = 12.75 \] ### Step 5: Solve for the breadth (B) Now, subtract 9.5 from both sides to find \( B \): \[ B = 12.75 - 9.5 \] Calculating this gives: \[ B = 3.25 \, \text{m} \] ### Step 6: Calculate the area of the rectangle The area (A) of a rectangle is given by the formula: \[ A = L \times B \] Substituting the values of \( L \) and \( B \): \[ A = 9.5 \times 3.25 \] ### Step 7: Perform the multiplication Calculating the area: \[ A = 30.875 \, \text{m}^2 \] ### Final Answer The area of the rectangle is \( 30.875 \, \text{m}^2 \). ---
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