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In trapezium ABCD, AB//DC. M is mid poin...

In trapezium ABCD, AB//DC. M is mid point of AD and N is mid-point of BC.
If AB = 5.7 cm and MN = 6.2 cm , find DC.

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To solve the problem, we need to find the length of side DC in trapezium ABCD where AB is parallel to DC, and M and N are the midpoints of sides AD and BC, respectively. ### Step-by-Step Solution: 1. **Identify the Given Information:** - AB = 5.7 cm - MN = 6.2 cm - M is the midpoint of AD. - N is the midpoint of BC. 2. **Use the Midsegment Theorem:** The length of the segment connecting the midpoints of the non-parallel sides (MN) in a trapezium is given by the formula: \[ MN = \frac{AB + DC}{2} \] Here, we need to find DC. 3. **Set Up the Equation:** From the Midsegment Theorem, we can write: \[ 6.2 = \frac{5.7 + DC}{2} \] 4. **Multiply Both Sides by 2:** To eliminate the fraction, multiply both sides by 2: \[ 2 \times 6.2 = 5.7 + DC \] \[ 12.4 = 5.7 + DC \] 5. **Isolate DC:** Now, we can isolate DC by subtracting 5.7 from both sides: \[ DC = 12.4 - 5.7 \] 6. **Calculate DC:** Perform the subtraction: \[ DC = 6.7 \text{ cm} \] ### Final Answer: DC = 6.7 cm
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