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If the difference between an interior angle of a regular polygon of (n + 1) sides and an interior angle of a regular polygon of n sides is` 4^(@) `, find the value of n. Also, state the difference between their exterior angles.

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To solve the problem step by step, we will find the value of \( n \) such that the difference between the interior angles of a regular polygon with \( n+1 \) sides and a polygon with \( n \) sides is \( 4^\circ \). We will also find the difference between their exterior angles. ### Step 1: Write the formula for the interior angle of a regular polygon The interior angle \( A \) of a regular polygon with \( n \) sides is given by the formula: \[ A = \frac{180(n - 2)}{n} \] ### Step 2: Write the interior angles for \( n \) and \( n + 1 \) sides - For a polygon with \( n \) sides: \[ A_n = \frac{180(n - 2)}{n} \] - For a polygon with \( n + 1 \) sides: \[ A_{n+1} = \frac{180((n + 1) - 2)}{n + 1} = \frac{180(n - 1)}{n + 1} \] ### Step 3: Set up the equation for the difference of the interior angles According to the problem, the difference between the interior angles is \( 4^\circ \): \[ A_{n+1} - A_n = 4 \] Substituting the expressions for \( A_{n+1} \) and \( A_n \): \[ \frac{180(n - 1)}{n + 1} - \frac{180(n - 2)}{n} = 4 \] ### Step 4: Simplify the equation Taking \( 180 \) common: \[ 180 \left( \frac{n - 1}{n + 1} - \frac{n - 2}{n} \right) = 4 \] Dividing both sides by \( 180 \): \[ \frac{n - 1}{n + 1} - \frac{n - 2}{n} = \frac{4}{180} = \frac{1}{45} \] ### Step 5: Find a common denominator and simplify The common denominator for the fractions is \( n(n + 1) \): \[ \frac{(n - 1)n - (n - 2)(n + 1)}{n(n + 1)} = \frac{1}{45} \] Expanding the numerator: \[ (n^2 - n) - (n^2 + n - 2) = n^2 - n - n^2 - n + 2 = -2n + 2 \] So we have: \[ \frac{-2n + 2}{n(n + 1)} = \frac{1}{45} \] ### Step 6: Cross-multiply to solve for \( n \) Cross-multiplying gives: \[ -2n + 2 = \frac{n(n + 1)}{45} \] Multiplying both sides by \( 45 \): \[ -90n + 90 = n(n + 1) \] Rearranging the equation: \[ n^2 + 91n - 90 = 0 \] ### Step 7: Factor the quadratic equation Factoring: \[ (n - 9)(n + 10) = 0 \] Thus, \( n = 9 \) or \( n = -10 \). Since \( n \) must be positive, we have: \[ n = 9 \] ### Step 8: Find the difference in exterior angles The exterior angle \( E \) of a regular polygon with \( n \) sides is given by: \[ E = \frac{360}{n} \] For \( n = 9 \): \[ E_n = \frac{360}{9} = 40^\circ \] For \( n + 1 = 10 \): \[ E_{n+1} = \frac{360}{10} = 36^\circ \] The difference in exterior angles is: \[ E_n - E_{n+1} = 40^\circ - 36^\circ = 4^\circ \] ### Final Answer Thus, the value of \( n \) is \( 9 \), and the difference between their exterior angles is \( 4^\circ \). ---
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ICSE-CHAPTERWISE REVISION (STAGE 1) -Rectillinear figures
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