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Two chords AB and CD of lengths 24 cm an...

Two chords AB and CD of lengths 24 cm and 10 cm respectively of a circle are parallel. If the chords lie on the same side of the centre and distance between them is 7 cm, find the length of a diameter of the circle.

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To find the diameter of the circle given the lengths of two parallel chords and the distance between them, we can follow these steps: ### Step 1: Understand the Problem We have two chords AB and CD of lengths 24 cm and 10 cm, respectively. The distance between the two chords is 7 cm. We need to find the diameter of the circle. ### Step 2: Bisect the Chords Since the chords are parallel, we can drop perpendiculars from the center of the circle to each chord. Let’s denote the midpoint of AB as M and the midpoint of CD as N. - Length of AB = 24 cm, so AM = MB = 12 cm (since M bisects AB). - Length of CD = 10 cm, so CN = ND = 5 cm (since N bisects CD). ### Step 3: Set Up the Geometry Let the distance from the center of the circle to chord AB be \( h \) and the distance from the center to chord CD be \( h + 7 \) (since the distance between the two chords is 7 cm). ### Step 4: Apply the Pythagorean Theorem We can apply the Pythagorean theorem in triangles formed by the radius, the half-length of the chord, and the distance from the center to the chord. For chord AB: \[ r^2 = h^2 + 12^2 \] \[ r^2 = h^2 + 144 \quad \text{(1)} \] For chord CD: \[ r^2 = (h + 7)^2 + 5^2 \] \[ r^2 = (h + 7)^2 + 25 \quad \text{(2)} \] ### Step 5: Expand Equation (2) Expanding equation (2): \[ r^2 = (h^2 + 14h + 49) + 25 \] \[ r^2 = h^2 + 14h + 74 \quad \text{(3)} \] ### Step 6: Set Equations Equal Since both equations (1) and (3) equal \( r^2 \), we can set them equal to each other: \[ h^2 + 144 = h^2 + 14h + 74 \] ### Step 7: Simplify the Equation Cancel \( h^2 \) from both sides: \[ 144 = 14h + 74 \] Subtract 74 from both sides: \[ 70 = 14h \] Divide by 14: \[ h = 5 \] ### Step 8: Find the Radius Now substitute \( h = 5 \) back into equation (1) to find the radius: \[ r^2 = 5^2 + 144 \] \[ r^2 = 25 + 144 \] \[ r^2 = 169 \] Taking the square root: \[ r = 13 \, \text{cm} \] ### Step 9: Calculate the Diameter The diameter \( D \) of the circle is given by: \[ D = 2r \] \[ D = 2 \times 13 = 26 \, \text{cm} \] ### Final Answer The length of the diameter of the circle is **26 cm**.
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