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Calculate the distance between A (7,3) and B on the x-axis whose abscissa is 11.

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To calculate the distance between the points A(7, 3) and B(11, 0), we can follow these steps: ### Step 1: Identify the coordinates of the points - Point A is given as A(7, 3). - Point B is on the x-axis with an abscissa of 11, so its coordinates are B(11, 0). ### Step 2: Use the distance formula The distance \( d \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by the formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] ### Step 3: Substitute the coordinates into the formula Here, \( (x_1, y_1) = (7, 3) \) and \( (x_2, y_2) = (11, 0) \). Substituting these values into the distance formula: \[ d = \sqrt{(11 - 7)^2 + (0 - 3)^2} \] ### Step 4: Simplify the expression Calculate \( (11 - 7) \) and \( (0 - 3) \): \[ d = \sqrt{(4)^2 + (-3)^2} \] \[ d = \sqrt{16 + 9} \] ### Step 5: Final calculation Now, add the squares: \[ d = \sqrt{25} \] \[ d = 5 \] ### Conclusion The distance between points A(7, 3) and B(11, 0) is 5 units. ---
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ICSE-CHAPTERWISE REVISION (STAGE 1) -co-ordinate Geometry
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  11. Find the distances between the points (2,-5) and (7,7)

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  12. If A = (x,-7 ) , B = (2,5) and AB = 13 units , findx.

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  13. A is a point on x- axis, and point B (5,-4) and AB = 5 units find t...

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  14. Show that A (0,0) , B(5,5) and C (-5,5) are vertices of a right ang...

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  15. Show that the points A(6,4) , B(9,7) and C(11,9) are collinear.

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