Home
Class 9
MATHS
ax + by = c bx+ ay =1 +c...

` ax + by = c`
` bx+ ay =1 +c`

Text Solution

Verified by Experts

The correct Answer is:
` x = 100 and y = 50`
Promotional Banner

Topper's Solved these Questions

  • CHAPTER REVISION (STAGE 2)

    ICSE|Exercise INDICES |6 Videos

  • CHAPTER REVISION (STAGE 2)

    ICSE|Exercise LOGRITHMS |8 Videos

  • CHAPTER REVISION (STAGE 2)

    ICSE|Exercise FACTRORISATIONS |10 Videos

  • AREA THEOREMS

    ICSE|Exercise Exercies 16(C )|22 Videos

  • CHAPTERWISE REVISION (STAGE 1)

    ICSE|Exercise Graphical solution |10 Videos

Similar Questions

Explore conceptually related problems

if a gt b gt c and the system of equations ax + by + cz = 0, bx + cy + az 0 and cx + ay + bz = 0 has a non-trivial solution, then the quadratic equation ax^(2) + bx + c =0 has

STATEMENT-1 : If a, b, c are distinct and x, y, z are not all zero and ax + by + cz = 0, bx + cy + az = 0, cx + ay + bz = 0 , then a + b + c = 0 and STATEMENT-2 : a^2 + b^2 + c^2 > ab + bc + ca , if a, b, c are distinct.

If a !=b , then the system of equation ax + by + bz = 0 bx + ay + bz = 0 and bx + by + az = 0 will have a non-trivial solution, if

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}

The the area bounded by the curve |x| + |y| = c (c > 0) is 2c^(2) , then the area bounded by |ax + by| + |bx - ay| = c where b^(2) - a^(2) = 1 is

If the system of equations bx + ay = c, cx + az = b, cy + bz = a has a unique solution, then

If a gt b gt c and the system of equtions ax +by +cz =0 , bx +cy+az=0 , cx+ay+bz=0 has a non-trivial solution then both the roots of the quadratic equation at^(2)+bt+c are

If the roots of the equation ax^2 + bx + c = 0, a != 0 (a, b, c are real numbers), are imaginary and a + c < b, then

Factorise : (v) (ax + by )^(2) + (bx - ay)^(2)

Find the value of x and y: ax +by =a-b bx-ay =a+b