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Beaker A contains sugаr solution with 18...

Beaker A contains sugаr solution with 18 percent sugar. beaker B contains sugar solution with 12 percent sugar. How much of each must he mixed together to get solution of 16 percent sugar weighing 240 gm of it?

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To solve the problem of mixing two sugar solutions to achieve a desired concentration, we can follow these steps: ### Step 1: Define Variables Let: - \( x \) = weight of Beaker A (18% sugar solution) - \( y \) = weight of Beaker B (12% sugar solution) ### Step 2: Set Up the First Equation According to the problem, the total weight of the mixture is 240 grams. Therefore, we can write the first equation as: \[ x + y = 240 \] ### Step 3: Set Up the Second Equation Next, we need to account for the sugar content in the mixtures. The total sugar in the final solution should be equal to 16% of 240 grams. Thus, we can write the second equation as: \[ 0.18x + 0.12y = 0.16 \times 240 \] ### Step 4: Simplify the Second Equation Calculating \( 0.16 \times 240 \): \[ 0.16 \times 240 = 38.4 \] So the second equation becomes: \[ 0.18x + 0.12y = 38.4 \] ### Step 5: Eliminate Decimals To eliminate decimals, we can multiply the entire second equation by 100: \[ 18x + 12y = 3840 \] ### Step 6: Rearrange the First Equation From the first equation \( x + y = 240 \), we can express \( x \) in terms of \( y \): \[ x = 240 - y \] ### Step 7: Substitute in the Second Equation Now, substitute \( x = 240 - y \) into the second equation: \[ 18(240 - y) + 12y = 3840 \] ### Step 8: Distribute and Combine Like Terms Distributing gives: \[ 4320 - 18y + 12y = 3840 \] Combine like terms: \[ 4320 - 6y = 3840 \] ### Step 9: Solve for \( y \) Rearranging gives: \[ -6y = 3840 - 4320 \] \[ -6y = -480 \] Dividing both sides by -6: \[ y = 80 \] ### Step 10: Solve for \( x \) Now substitute \( y = 80 \) back into the first equation: \[ x + 80 = 240 \] \[ x = 240 - 80 \] \[ x = 160 \] ### Conclusion The weights of the solutions to be mixed are: - Weight of Beaker A (18% solution) = 160 grams - Weight of Beaker B (12% solution) = 80 grams
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