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Solve for x: log(4) (2x+3) =(3)/(2)...

Solve for x:
` log_(4) (2x+3) =(3)/(2)`

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To solve the equation \( \log_{4}(2x + 3) = \frac{3}{2} \), we will follow these steps: ### Step 1: Convert the logarithmic equation to its exponential form. The logarithmic equation \( \log_{4}(2x + 3) = \frac{3}{2} \) can be rewritten in exponential form as: \[ 2x + 3 = 4^{\frac{3}{2}} \] ### Step 2: Calculate \( 4^{\frac{3}{2}} \). We know that \( 4^{\frac{3}{2}} \) can be calculated as follows: \[ 4^{\frac{3}{2}} = (4^{\frac{1}{2}})^3 = (2)^3 = 8 \] So, we have: \[ 2x + 3 = 8 \] ### Step 3: Isolate \( x \). Now, we will isolate \( x \) by subtracting 3 from both sides: \[ 2x = 8 - 3 \] \[ 2x = 5 \] ### Step 4: Solve for \( x \). Next, we divide both sides by 2: \[ x = \frac{5}{2} \] ### Final Answer: Thus, the solution for \( x \) is: \[ x = 2.5 \] ---
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