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The perimeter of a parallelogram ABCD ...

The perimeter of a parallelogram ABCD = 40 cm , AB = 3x cm, BC = 2x cm and CD = 2( y+1) cm . Find the values of x and y.

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To solve the problem, we will follow these steps: ### Step 1: Understand the properties of a parallelogram In a parallelogram, opposite sides are equal. Therefore, we can set up equations based on the given information. ### Step 2: Set up the equations Given: - Perimeter of parallelogram ABCD = 40 cm - AB = 3x cm - BC = 2x cm - CD = 2(y + 1) cm = 2y + 2 cm Since opposite sides are equal: - AD = BC = 2x cm - CD = AB = 3x cm ### Step 3: Write the perimeter equation The perimeter (P) of a parallelogram is given by the formula: \[ P = 2(AB + BC) \] Substituting the values we have: \[ 40 = 2(3x + 2x) \] ### Step 4: Simplify the perimeter equation Now we simplify the equation: \[ 40 = 2(5x) \] \[ 40 = 10x \] ### Step 5: Solve for x To find x, divide both sides by 10: \[ x = \frac{40}{10} \] \[ x = 4 \] ### Step 6: Use the value of x to find y Now we know that AB = 3x and CD = 2y + 2. Since AB = CD: \[ 3x = 2y + 2 \] Substituting the value of x: \[ 3(4) = 2y + 2 \] \[ 12 = 2y + 2 \] ### Step 7: Solve for y Now, isolate y: \[ 12 - 2 = 2y \] \[ 10 = 2y \] \[ y = \frac{10}{2} \] \[ y = 5 \] ### Final Answer Thus, the values are: - \( x = 4 \) - \( y = 5 \) ---
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