Draw graph of linear equations 4x-3y +12 =0. Use graph drawn fo find:
x. when y = 4

Answer

To solve the problem of drawing the graph of the linear equation \(4x - 3y + 12 = 0\) and finding the value of \(x\) when \(y = 4\), we can follow these steps:

### Step 1: Rewrite the Equation
First, we will rewrite the equation in the slope-intercept form (y = mx + b) to make it easier to plot the graph.

\[ 4x - 3y + 12 = 0 \]

Rearranging gives:

\[ -3y = -4x - 12 \]

Dividing by -3:

\[ y = \frac{4}{3}x + 4 \]

### Step 2: Create a Table of Values
Next, we will create a table of values for \(x\) and \(y\) by substituting different values of \(x\) into the equation.

| \(x\) | \(y\) |
|-------|------------------|
| 0 | \(4\) |
| -1 | \(\frac{8}{3} \approx 2.67\) |
| -2 | \(\frac{4}{3} \approx 1.33\) |
| -3 | \(0\) |

### Step 3: Plot the Points
Now we will plot the points on a graph:

1. \( (0, 4) \)
2. \( (-1, \frac{8}{3}) \)
3. \( (-2, \frac{4}{3}) \)
4. \( (-3, 0) \)

### Step 4: Draw the Line
Using a ruler, connect the plotted points to form a straight line. This line represents the equation \(4x - 3y + 12 = 0\).

### Step 5: Find \(x\) when \(y = 4\)
From our table, we can see that when \(y = 4\), the corresponding value of \(x\) is \(0\).

### Final Answer
Thus, the value of \(x\) when \(y = 4\) is:

\[ \boxed{0} \]

---