Any point D is taken on the side BC of a ` Delta ABC ` and AD is produced to E such that AD = DE , prove that area of `Delta BCE = ` area of `Delta ABC`,

In a Delta ABC , BD is the median to the side AC, BD is produced to E such that BD = DE. Prove that : AE is parallel to BC.

If D is a Point on the side BC of a Delta ABC such that AD bisects angleBAC . Then

In the adjoining figure, D is the mid-point of side AB of Delta ABC and P be any point on side BC. If CQ ||PD , then prove that: area of Delta BPQ = (1)/(2) xx " area of " Delta ABC

In a triangle ABC,D is the mid - point of BC, AD is produced upto E so that DE = AD. Prove that : AB=EC

If D id the mid-point of the side BC of a triangle ABC and AD is perpendicular to AC , then

In triangle ABC, D is a point in side BC such that 2BD=3DC . Prove that the area of triangle ABD = (3)/(5)xx "Area of" DeltaABC

The medians of Delta ABC intersect at point G. Prove that: area of Delta AGB = (1)/(3) xx " area of " Delta ABC

In Delta ABC ,D is a point in side AB and E is a point in AC. If DE is parallel to BC, and BE and CD intersect each other at point 0, prove that: " area " (Delta OBD) = " area " (Delta OCE)

In the adjoining figure, AD is the median of Delta ABC and X be any point on side AD. Prove that: area (Delta ABX) = " area " (Delta ACX)

Delta ABC and Delta DBC are on same base BC and their vertices A and D are on opposite sides of BC. It is given that: area of Delta ABC = " area of " Delta DBC Prove that BC bisects the line segment AD.