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Deepa has a 4 - year recurring deposit a...

Deepa has a `4` - year recurring deposit account in a bank and deposits `₹ 1,800` per month. If she gets `₹ 1,08,450` at the time of maturity, find the rate of interest.

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To find the rate of interest for Deepa's recurring deposit account, we can follow these steps: ### Step 1: Identify the given values - Monthly deposit (P) = ₹1,800 - Duration of the deposit = 4 years - Total maturity amount = ₹1,08,450 ### Step 2: Calculate the total number of months Since Deepa deposits money for 4 years, we need to convert this into months: \[ \text{Number of months (n)} = 4 \times 12 = 48 \text{ months} \] ### Step 3: Use the formula for Simple Interest (SI) for Recurring Deposits The formula for the Simple Interest (SI) for a recurring deposit is: \[ SI = P \times \frac{n(n + 1)}{2} \times \frac{r}{100 \times 12} \] Where: - \( P \) = monthly deposit - \( n \) = number of months - \( r \) = rate of interest per annum ### Step 4: Substitute the known values into the SI formula Substituting \( P = 1800 \) and \( n = 48 \): \[ SI = 1800 \times \frac{48 \times (48 + 1)}{2} \times \frac{r}{100 \times 12} \] Calculating \( n(n + 1) \): \[ 48 \times 49 = 2352 \] Now substituting this back: \[ SI = 1800 \times \frac{2352}{2} \times \frac{r}{1200} \] Calculating \( \frac{2352}{2} = 1176 \): \[ SI = 1800 \times 1176 \times \frac{r}{1200} \] ### Step 5: Simplify the SI expression \[ SI = 1800 \times 1176 \div 1200 \times r \] Calculating \( 1800 \div 1200 = 1.5 \): \[ SI = 1.5 \times 1176 \times r \] Calculating \( 1.5 \times 1176 = 1764 \): \[ SI = 1764r \] ### Step 6: Relate SI to the maturity amount The maturity amount (M) is given by: \[ M = \text{Total deposits} + SI \] The total deposits over 48 months: \[ \text{Total deposits} = 1800 \times 48 = 86400 \] Thus, we have: \[ 1,08,450 = 86400 + 1764r \] ### Step 7: Solve for r Rearranging the equation: \[ 1764r = 1,08,450 - 86400 \] Calculating the right side: \[ 1,08,450 - 86400 = 22,050 \] So: \[ 1764r = 22,050 \] Now, divide both sides by 1764: \[ r = \frac{22,050}{1764} \] ### Step 8: Calculate r Calculating the division: \[ r \approx 12.5 \] ### Conclusion The rate of interest \( r \) is approximately: \[ \text{Rate of interest} = 12.5\% \text{ per annum} \] ---
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