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List the solution set of 50 - 3 (2x - 5)...

List the solution set of 50 - 3 (2x - 5) `lt` 25, given that `x in W`. Also, represent the solution set obtained on a number line.

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To solve the inequality \( 50 - 3(2x - 5) < 25 \) and find the solution set for \( x \) in whole numbers, we will follow these steps: ### Step 1: Simplify the inequality Start with the original inequality: \[ 50 - 3(2x - 5) < 25 \] Distribute the \(-3\) inside the parentheses: \[ 50 - 6x + 15 < 25 \] Combine like terms: \[ 65 - 6x < 25 \] ### Step 2: Isolate the variable Subtract \(65\) from both sides: \[ -6x < 25 - 65 \] This simplifies to: \[ -6x < -40 \] ### Step 3: Divide by -6 When dividing by a negative number, remember to reverse the inequality sign: \[ x > \frac{-40}{-6} \] This simplifies to: \[ x > \frac{40}{6} \] Which further simplifies to: \[ x > 6.67 \] ### Step 4: Determine the solution set in whole numbers Since \(x\) must be greater than \(6.67\) and \(x\) belongs to whole numbers, the smallest whole number satisfying this inequality is \(7\). Therefore, the solution set in whole numbers is: \[ \{7, 8, 9, 10, \ldots\} \] ### Step 5: Represent the solution set on a number line To represent this on a number line, we will mark the point \(6.67\) and draw an open circle at this point to indicate that it is not included in the solution. Then, we shade the region to the right of \(6.67\) to represent all whole numbers greater than \(6.67\). ### Final Answer The solution set is: \[ \{7, 8, 9, 10, \ldots\} \] On the number line, it is represented as: - An open circle at \(6.67\) and shading to the right. ---
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Knowledge Check

  • The solution set of -1 le 3+ 4x lt 23, x in W is

    A
    {0, 1, 2, 3, 4}
    B
    `{-1, 0, 1, 2,3,4}`
    C
    {0,1,2,3,4,5}
    D
    `{-1, 0,1,2,3,4,5}`
  • The solution set of -12 lt 4 -(3x)/(-5) le 2 , x in R is

    A
    `(10/3,80/3]`
    B
    `[-80/3,10/3)`
    C
    `(-80/3,-10/3]`
    D
    `(80/3,-10/3)`
  • The solution set of -1 lt 3 -2x lt 9, x in I is .....

    A
    `{-2, -,1, 0,1}`
    B
    `{-3, -2, -1, 0,1,2}`
    C
    `{-2, -1, 0,1,2}`
    D
    `{-3, -2, -1,0,1}`
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