The line given by the equation `2x - y/3 = 7` passes through the point `(k, 6)`, calculate the value of k. 

Answer

To find the value of \( k \) such that the line given by the equation \( 2x - \frac{y}{3} = 7 \) passes through the point \( (k, 6) \), we will follow these steps:

### Step 1: Substitute the point into the equation
Since the point \( (k, 6) \) lies on the line, we can substitute \( x = k \) and \( y = 6 \) into the equation of the line.

\[ 2k - \frac{6}{3} = 7 \]

### Step 2: Simplify the equation
Now, simplify the left side of the equation. We know that \( \frac{6}{3} = 2 \), so we can rewrite the equation as:

\[ 2k - 2 = 7 \]

### Step 3: Solve for \( k \)
Next, we will isolate \( k \) by adding 2 to both sides of the equation:

\[ 2k = 7 + 2 \]

This simplifies to:

\[ 2k = 9 \]

Now, divide both sides by 2 to solve for \( k \):

\[ k = \frac{9}{2} \]

### Final Answer
The value of \( k \) is \( \frac{9}{2} \).

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