The line `y = mx + 8` contains the point (-4, 4), calculate the value of m. 

Answer

To find the value of \( m \) for the line \( y = mx + 8 \) that contains the point \((-4, 4)\), we can follow these steps:

### Step 1: Substitute the point into the line equation
We know that the point \((-4, 4)\) lies on the line. Therefore, we can substitute \( x = -4 \) and \( y = 4 \) into the equation \( y = mx + 8 \).

\[ 4 = m(-4) + 8 \]

### Step 2: Simplify the equation
Now, we simplify the equation:

\[ 4 = -4m + 8 \]

### Step 3: Isolate the term with \( m \)
Next, we want to isolate the term with \( m \). We can do this by moving \( 8 \) to the left side of the equation:

\[ 4 - 8 = -4m \]

This simplifies to:

\[ -4 = -4m \]

### Step 4: Solve for \( m \)
Now, we can solve for \( m \) by dividing both sides of the equation by \(-4\):

\[ m = \frac{-4}{-4} = 1 \]

### Conclusion
Thus, the value of \( m \) is \( 1 \).

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