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The equation of a line is 3x + 4y - 7 = ...

The equation of a line is `3x + 4y - 7 = 0`. Find:
the equation of a line perpendicular to the given line and passing through the intersection of the lines `x - y + 2 = 0` and `3x + y - 10 = 0`.

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To solve the problem step by step, we will follow these procedures: ### Step 1: Find the Intersection Point of the Given Lines We need to find the intersection of the lines given by the equations: 1. \( x - y + 2 = 0 \) (let's call this line L1) 2. \( 3x + y - 10 = 0 \) (let's call this line L2) To find the intersection, we can solve these equations simultaneously. **From L1:** \[ x - y + 2 = 0 \implies y = x + 2 \] **Substituting \(y\) in L2:** \[ 3x + (x + 2) - 10 = 0 \] \[ 3x + x + 2 - 10 = 0 \] \[ 4x - 8 = 0 \implies 4x = 8 \implies x = 2 \] **Now, substituting \(x = 2\) back into L1 to find \(y\):** \[ y = 2 + 2 = 4 \] Thus, the intersection point \(I\) is \((2, 4)\). ### Step 2: Find the Slope of the Given Line The equation of the given line is: \[ 3x + 4y - 7 = 0 \] We can rearrange this into the slope-intercept form \(y = mx + c\): \[ 4y = -3x + 7 \implies y = -\frac{3}{4}x + \frac{7}{4} \] The slope \(m_4\) of this line is: \[ m_4 = -\frac{3}{4} \] ### Step 3: Find the Slope of the Perpendicular Line For a line to be perpendicular to another, the product of their slopes must equal \(-1\): \[ m_3 \cdot m_4 = -1 \] Substituting \(m_4\): \[ m_3 \cdot \left(-\frac{3}{4}\right) = -1 \implies m_3 = \frac{4}{3} \] ### Step 4: Use the Point-Slope Form to Write the Equation of the Required Line Now we have the slope \(m_3 = \frac{4}{3}\) and the point \(I(2, 4)\). We can use the point-slope form of the equation of a line: \[ y - y_1 = m(x - x_1) \] Substituting \(m = \frac{4}{3}\), \(x_1 = 2\), and \(y_1 = 4\): \[ y - 4 = \frac{4}{3}(x - 2) \] ### Step 5: Rearranging to Standard Form Now we rearrange the equation: \[ y - 4 = \frac{4}{3}x - \frac{8}{3} \] Multiplying through by 3 to eliminate the fraction: \[ 3y - 12 = 4x - 8 \] Rearranging gives: \[ 3y - 4x = 4 \] ### Final Equation Thus, the equation of the line perpendicular to the given line and passing through the intersection point is: \[ 3y - 4x = 4 \] ---
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ICSE-EQUATION OF A LINE-EXERCISE 14(E)
  1. A and B are two points on the x-axis and y-axis respectively. P(2, -3)...

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  2. The equation of a line is 3x + 4y - 7 = 0. Find: the slope of the li...

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  3. The equation of a line is 3x + 4y - 7 = 0. Find: the equation of a l...

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  4. ABCD is a parallelogram where A(x, y), B(5, 8), C(4, 7) and D(2, -4). ...

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  5. ABCD is a parallelogram where A (x, y), B (5, 8), C (4, 7) and D 2, -4...

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  6. Given equation of line L1 is y = 4   Write the slope of line L1 if...

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  7. Given equation of line L1 is y = 4    Write the co-ordinates of po...

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  8. Given equation of line L1 is y = 4   Find the equation of L2.

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  9. Find :   equation of AB

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  10. Find : equation of CD

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  11. Find the equation of the line that has x-intercept = -3 and is perpend...

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  12. A straight line passes through the points P(-1, 4) and Q(5,-2). It int...

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  13. A straight line passes through the points P(-1, 4) and Q(5,-2). It int...

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  14. A straight line passes through the points P(-1, 4) and Q(5,-2). It int...

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  15. In the given figure, line AB meets y-axis at point A. Line through C(2...

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  16. In the given figure, line AB meets y-axis at point A. Line through C(2...

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  17. In the given figure, line AB meets y-axis at point A. Line through C(2...

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  18. A line through point P(4, 3) meets x-axis at point A and the y-axis at...

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  19. Find the equation of line through the intersection of lines 2x - y = 1...

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  20. Find the equation of the line through the points A(-1, 3) and B(0, 2)....

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