Home
Class 10
MATHS
A rectangular tank has length = 4 m, wid...

A rectangular tank has length = 4 m, width = 3 m and capacity = `30 m^3`. A small model of the tank is made with capacity `240 cm^3`. Find :
the ratio between the total surface area of the tank and its model.

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio between the total surface area of the rectangular tank and its model, we will follow these steps: ### Step 1: Calculate the height of the tank The volume (capacity) of the tank is given by the formula: \[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \] Given: - Length = 4 m - Width = 3 m - Volume = 30 m³ We can rearrange the formula to find the height: \[ \text{Height} = \frac{\text{Volume}}{\text{Length} \times \text{Width}} = \frac{30}{4 \times 3} = \frac{30}{12} = 2.5 \text{ m} \] ### Step 2: Calculate the total surface area of the tank The total surface area (TSA) of a rectangular prism is given by the formula: \[ \text{TSA} = 2(\text{Length} \times \text{Width} + \text{Width} \times \text{Height} + \text{Height} \times \text{Length}) \] Substituting the values: \[ \text{TSA}_{\text{tank}} = 2(4 \times 3 + 3 \times 2.5 + 2.5 \times 4) \] Calculating each term: - \(4 \times 3 = 12\) - \(3 \times 2.5 = 7.5\) - \(2.5 \times 4 = 10\) Now substituting back: \[ \text{TSA}_{\text{tank}} = 2(12 + 7.5 + 10) = 2(29.5) = 59 \text{ m}^2 \] ### Step 3: Calculate the total surface area of the model The volume of the model is given as 240 cm³. We will assume dimensions that satisfy this volume. Let's take: - Length = 15 cm - Width = 8 cm - Height = 2 cm Now, we can verify the volume: \[ \text{Volume}_{\text{model}} = 15 \times 8 \times 2 = 240 \text{ cm}^3 \] Now, calculate the total surface area of the model using the same TSA formula: \[ \text{TSA}_{\text{model}} = 2(15 \times 8 + 8 \times 2 + 2 \times 15) \] Calculating each term: - \(15 \times 8 = 120\) - \(8 \times 2 = 16\) - \(2 \times 15 = 30\) Now substituting back: \[ \text{TSA}_{\text{model}} = 2(120 + 16 + 30) = 2(166) = 332 \text{ cm}^2 \] ### Step 4: Convert the surface area of the tank to cm² Since 1 m² = 10,000 cm², we convert the surface area of the tank: \[ \text{TSA}_{\text{tank}} = 59 \text{ m}^2 = 59 \times 10,000 = 590,000 \text{ cm}^2 \] ### Step 5: Calculate the ratio of the total surface areas Now we can find the ratio of the total surface area of the tank to that of the model: \[ \text{Ratio} = \frac{\text{TSA}_{\text{tank}}}{\text{TSA}_{\text{model}}} = \frac{590,000 \text{ cm}^2}{332 \text{ cm}^2} \] Calculating the ratio: \[ \text{Ratio} \approx 1771:1 \] ### Final Answer The ratio between the total surface area of the tank and its model is approximately \(1771:1\). ---
Promotional Banner

Topper's Solved these Questions

  • SIMILARITY (WITH APPLICATIONS TO MAPS AND MODELS)

    ICSE|Exercise EXERCISE 15(A)|48 Videos
  • SIMILARITY (WITH APPLICATIONS TO MAPS AND MODELS)

    ICSE|Exercise EXERCISE 15(B)|17 Videos
  • SIMILARITY

    ICSE|Exercise MULTIPLE CHOICE QUESTIONS (COMPETENCY BASED QUESTIONS)|10 Videos
  • SOLVING (SIMPLE) PROBLEMS (BASED ON QUADRATIC EQUATIONS)

    ICSE|Exercise Exercise 6(e )|18 Videos

Similar Questions

Explore conceptually related problems

A rectangular tank has length = 4 m, width = 3 m and capacity = 30 m^3 . A small model of the tank is made with capacity 240 cm^3 . Find : the dimensions of the model.

A model of a ship is made to a scale of 1:160 . Find: the area of the deck of the ship, if the area of the deck of its model is 1.2m^(2)

A closed rectangular tank 10 m long, 5 m wide and 3 m deep is completely filled with an oil of specific gravity 0.92 . Find the pressure difference between the rear and front corners of the tank, if it is moving with an acceleration of 3m//s^(2) in the horizontal direction.

The height of a tower is 200 m. A model of this tower is made such that the ratio between the height of the actual tower and that of the model is 160:1. Find the height of the model.

The height of a tower is 132m. A model of this tower is made such that the ratio between the height of the actual tower and that of the model is 120:1. Find the height of the model.

The length, breadth and height of a cuboid are in the ratio 5 : 3 : 2. If its volume is 240 cm^(3) , find its dimensions. Also find the total surface area of the cuboid.

The length the breadth and the height of a cuboid are in the ratio 5: 3: 2 If its volume is 240 cm ^(3) find its dimensions. Also find the total surface area of the cuboid.

The dimensions of a cuboid are in the ratio 5:3:1 and its total surface area is 414\ m^2dot Find the dimensions.

The dimensions of a cuboid are in the ratio of 1:2:3: and its total surface area is 88 m^2dot Find the dimensions.

The dimensions of a cuboid are in the ratio of 1:2:3: and its total surface area is 88 m^2dot Find the dimensions.

ICSE-SIMILARITY (WITH APPLICATIONS TO MAPS AND MODELS)-EXERCISE 15(E)
  1. A rectangular tank has length = 4 m, width = 3 m and capacity = 30 m^3...

    Text Solution

    |

  2. In the following figure, XY is parallel to BC, AX = 9 cm, XB = 4.5 cm ...

    Text Solution

    |

  3. In the following figure, XY is parallel to BC, AX = 9 cm, XB = 4.5 cm ...

    Text Solution

    |

  4. In the following figure, XY is parallel to BC, AX = 9 cm, XB = 4.5 cm ...

    Text Solution

    |

  5. In the following figure, ABCD to a trapezium with AB // DC. If AB = 9 ...

    Text Solution

    |

  6. In the following figure, ABCD to a trapezium with AB // DC. If AB = 9 ...

    Text Solution

    |

  7. In the following figure, ABCD to a trapezium with AB // DC. If AB = 9 ...

    Text Solution

    |

  8. In the following figure, AB, CD and EF are perpendicular to the straig...

    Text Solution

    |

  9. Triangle ABC is similar to triangle PQR. If AD and PM are correspondin...

    Text Solution

    |

  10. Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of...

    Text Solution

    |

  11. Triangle ABC is similar to triangle PQR. If bisector of angle BAC meet...

    Text Solution

    |

  12. In the following figure, /AXY = /AYX.. If (BX)/(AX) = (CY)/(AY) , show...

    Text Solution

    |

  13. In the following diagram, lines l, m and n are parallel to each other....

    Text Solution

    |

  14. In the following figure, DE||AC and DC||AP. Prove that : (BE)/(EC) = (...

    Text Solution

    |

  15. In the figure given below, AB // EF // CD. If AB = 22.5 cm, EP = 7.5 c...

    Text Solution

    |

  16. In the figure given below, AB // EF // CD. If AB = 22.5 cm, EP = 7.5 c...

    Text Solution

    |

  17. In DeltaABC, /ABC = /DAC, AB = 8 cm,AC = 4 cm and AD = 5 cm.   Pro...

    Text Solution

    |

  18. In DeltaABC, /ABC = /DAC, AB = 8 cm,AC = 4 cm and AD = 5 cm. Find...

    Text Solution

    |

  19. In DeltaABC, /ABC = /DAC, AB = 8 cm,AC = 4 cm and AD = 5 cm. Find...

    Text Solution

    |

  20. In the given triangle P, Q and R are the mid points of sides AB, BC an...

    Text Solution

    |

  21. In the following figure, AD and CE are medians of DeltaABC. DF is draw...

    Text Solution

    |