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In Delta ABC, D and E are the points on...

In `Delta ABC, D ` and E are the points on sides AB and AC respectively.
Find whether DE || BC, if :
  AB = 9 cm, AD = 4 cm, AE = 6 cm and EC = 7.5 cm. 

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The correct Answer is:
To determine whether line segment DE is parallel to line segment BC in triangle ABC, we can use the Converse of the Basic Proportionality Theorem (also known as the Thales theorem). This theorem states that if a line divides two sides of a triangle proportionally, then the line is parallel to the third side. ### Step-by-Step Solution: 1. **Identify the Given Values:** - AB = 9 cm - AD = 4 cm - AE = 6 cm - EC = 7.5 cm 2. **Calculate the Length of BD:** - Since D is a point on AB, we can find BD by subtracting AD from AB. \[ BD = AB - AD = 9 \text{ cm} - 4 \text{ cm} = 5 \text{ cm} \] 3. **Set Up the Proportions:** - We need to compare the ratios of the segments created by points D and E. - The ratio of AE to EC is: \[ \frac{AE}{EC} = \frac{6 \text{ cm}}{7.5 \text{ cm}} = \frac{6}{7.5} = \frac{4}{5} \] - The ratio of AD to BD is: \[ \frac{AD}{BD} = \frac{4 \text{ cm}}{5 \text{ cm}} = \frac{4}{5} \] 4. **Compare the Ratios:** - We observe that: \[ \frac{AE}{EC} = \frac{4}{5} \quad \text{and} \quad \frac{AD}{BD} = \frac{4}{5} \] - Since both ratios are equal, we can conclude that: \[ \frac{AE}{EC} = \frac{AD}{BD} \] 5. **Conclude Using the Converse of the Basic Proportionality Theorem:** - According to the Converse of the Basic Proportionality Theorem, if the segments are proportional, then DE is parallel to BC. - Therefore, we conclude that: \[ DE \parallel BC \] ### Final Answer: Yes, DE is parallel to BC.
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ICSE-SIMILARITY (WITH APPLICATIONS TO MAPS AND MODELS)-EXERCISE 15(B)
  1. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  2. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  3. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  4. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  5. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  6. In the given figure, PQ//AB, CQ = 4.8 cm QB = 3.6 cm and AB = 6-3 cm. ...

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  7. In the given figure, PQ//AB, CQ = 4.8 cm QB = 3.6 cm and AB = 6-3 cm. ...

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  8. In the given figure, PQ//AB, CQ = 4.8 cm QB = 3.6 cm and AB = 6-3 cm. ...

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  9. A line PQ is drawn parallel to the side BC of Delta ABC which cuts si...

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  10. In Delta ABC, D and E are the points on sides AB and AC respectively....

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  11. In Delta ABC, D and E are the points on sides AB and AC respectively....

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  12. In the given figure, DeltaABC ~ Delta ADE. If AE : EC = 4:7 and DE = 6...

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  13. A line segment DE is drawn parallel to base BC of A ABC which cuts AB ...

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  14. In the figure, given below, AB, CD and EF are parallel lines. Given AB...

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  15. In the figure, given below, PQR is a right angled triangle right angle...

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  16. In the following figure, M is mid-point of BC of a parallelogram ABCD....

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  17. The given figure shows a parallelogram ABCD. E is a point in AD and CE...

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