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A line segment DE is drawn parallel to b...

A line segment DE is drawn parallel to base BC of A ABC which cuts AB at point D and AC at point E. If AB = 5 BD and EC = 3.2 cm, find the length of AE. 

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To solve the problem step by step, we will use the properties of similar triangles. ### Step 1: Understand the relationship between segments Given that \( AB = 5 \times BD \), we can express \( AD \) in terms of \( BD \): \[ AD = AB - BD = 5BD - BD = 4BD \] ### Step 2: Set up the ratio of segments Now we can set up the ratio of the segments \( AD \) and \( AB \): \[ \frac{AD}{AB} = \frac{4BD}{5BD} = \frac{4}{5} \] ### Step 3: Use the property of similar triangles Since \( DE \) is parallel to \( BC \), triangles \( ADE \) and \( ABC \) are similar by the AA (Angle-Angle) similarity criterion. Therefore, the ratios of corresponding sides are equal: \[ \frac{AD}{AB} = \frac{AE}{AC} \] ### Step 4: Express \( AC \) in terms of \( AE \) We know that \( AC = AE + EC \). Given \( EC = 3.2 \) cm, we can substitute this into our ratio: \[ \frac{AD}{AB} = \frac{AE}{AE + 3.2} \] ### Step 5: Substitute the known values into the ratio Now, substituting the known values into the equation: \[ \frac{4}{5} = \frac{AE}{AE + 3.2} \] ### Step 6: Cross-multiply to solve for \( AE \) Cross-multiplying gives: \[ 4(AE + 3.2) = 5AE \] Expanding this: \[ 4AE + 12.8 = 5AE \] ### Step 7: Rearranging the equation Rearranging the equation to isolate \( AE \): \[ 12.8 = 5AE - 4AE \] \[ 12.8 = AE \] ### Step 8: Conclusion Thus, the length of \( AE \) is: \[ AE = 12.8 \, \text{cm} \] ---
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ICSE-SIMILARITY (WITH APPLICATIONS TO MAPS AND MODELS)-EXERCISE 15(B)
  1. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  2. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  3. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  4. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  5. In the following figure, point D divides AB in the ratio 3: 5. Find : ...

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  6. In the given figure, PQ//AB, CQ = 4.8 cm QB = 3.6 cm and AB = 6-3 cm. ...

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  7. In the given figure, PQ//AB, CQ = 4.8 cm QB = 3.6 cm and AB = 6-3 cm. ...

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  8. In the given figure, PQ//AB, CQ = 4.8 cm QB = 3.6 cm and AB = 6-3 cm. ...

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  9. A line PQ is drawn parallel to the side BC of Delta ABC which cuts si...

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  10. In Delta ABC, D and E are the points on sides AB and AC respectively....

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  11. In Delta ABC, D and E are the points on sides AB and AC respectively....

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  12. In the given figure, DeltaABC ~ Delta ADE. If AE : EC = 4:7 and DE = 6...

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  13. A line segment DE is drawn parallel to base BC of A ABC which cuts AB ...

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  14. In the figure, given below, AB, CD and EF are parallel lines. Given AB...

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  15. In the figure, given below, PQR is a right angled triangle right angle...

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  16. In the following figure, M is mid-point of BC of a parallelogram ABCD....

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  17. The given figure shows a parallelogram ABCD. E is a point in AD and CE...

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