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A vertical tower is 20 m high. A man sta...

A vertical tower is 20 m high. A man standing at some distance from the tower knows that the cosine of the angle of elevation of the top of the tower is 0.53. How far is he standing from the foot of the tower ?

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To solve the problem step by step, we will follow the approach outlined in the video transcript. ### Step 1: Understand the Problem We have a vertical tower of height 20 m and a man standing at a distance from the tower. The cosine of the angle of elevation of the top of the tower from the man's position is given as 0.53. We need to find the distance of the man from the foot of the tower. ### Step 2: Draw the Diagram Let's visualize the situation: - Let the point at the top of the tower be A. - Let the foot of the tower be B. - Let the position of the man be C. - The height of the tower (AB) is 20 m. - The distance from the foot of the tower to the man (BC) is x m. ### Step 3: Set Up the Relationship From the right triangle ABC, we know: - AB = 20 m (height of the tower) - BC = x m (distance from the tower) - AC = hypotenuse Using the cosine of the angle of elevation (θ): \[ \cos(θ) = \frac{BC}{AC} \] Given that \(\cos(θ) = 0.53\), we can write: \[ 0.53 = \frac{x}{AC} \] ### Step 4: Use Pythagorean Theorem To find AC, we can use the Pythagorean theorem: \[ AC = \sqrt{AB^2 + BC^2} = \sqrt{20^2 + x^2} = \sqrt{400 + x^2} \] ### Step 5: Substitute AC in the Cosine Equation Substituting AC in the cosine equation: \[ 0.53 = \frac{x}{\sqrt{400 + x^2}} \] ### Step 6: Square Both Sides To eliminate the square root, we square both sides: \[ 0.53^2 = \frac{x^2}{400 + x^2} \] Calculating \(0.53^2\): \[ 0.2809 = \frac{x^2}{400 + x^2} \] ### Step 7: Cross Multiply Cross multiplying gives: \[ 0.2809(400 + x^2) = x^2 \] Expanding this: \[ 112.36 + 0.2809x^2 = x^2 \] ### Step 8: Rearrange the Equation Rearranging the equation: \[ x^2 - 0.2809x^2 = 112.36 \] \[ 0.7191x^2 = 112.36 \] ### Step 9: Solve for x^2 Dividing both sides by 0.7191: \[ x^2 = \frac{112.36}{0.7191} \approx 156.25 \] ### Step 10: Find x Taking the square root of both sides: \[ x = \sqrt{156.25} = 12.5 \text{ m} \] ### Conclusion The distance of the man from the foot of the tower is **12.5 meters**. ---
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ICSE-HEIGHTS AND DISTANCES -Exercise 22 C
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  2. With reference to the given figure, a man stands on the ground at poin...

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  3. With reference to the given figure, a man stands on the ground at poin...

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  4. The angles of elevation of the top of a tower from two points at a dis...

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  5. From a window A , 10 m above the ground the angle of elevation of the...

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  6. A vertical tower is 20 m high. A man standing at some distance from th...

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  8. A man standing on the bank of a river observes that the angle of elev...

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  9. A 20 m high vertical pole and a vertical tower are on the same level g...

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  10. A 20 m high vertical pole and a vertical tower are on the same level g...

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  11. A vertical pole and a vertical tower are on the same level ground in ...

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  12. A vertical pole and a vertical tower are on the same level ground in ...

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  13. From a point 36 m above the surface of a lake , the angle of elevatio...

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  14. A man observes the angle of elevation of the top of a building to be 3...

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  15. As observed from the top of a 80 m tall lighthouse, the angle of dep...

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  16. In the given figure, A from the top of a building AB = 60 m high, the ...

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  17. In the figure given, from the top of a building AB = 60 m high, the an...

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  18. An aeroplane at an altitude of 250 m observes the angle of depression ...

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  19. The horizontal distance between two tower is 120 m. The angle of eleva...

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  20. The angles of depression of two ships a A and B as observed from the t...

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