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As observed from the top of a 80 m tal...

As observed from the top of a 80 m tall lighthouse, the angle of depression of two ships, on the same side of the light house in horizontal line with its base, are `30^(@) and 40^(@)` respectively . Find the distance between the two ships. Given your answer correct to the nearest metre

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To solve the problem step by step, we will use trigonometric principles to find the distances from the lighthouse to each ship and then calculate the distance between the two ships. ### Step 1: Draw the Diagram Draw a vertical line representing the lighthouse of height 80 m. Label the top of the lighthouse as point A and the base as point B. The two ships will be represented as points C and D on the horizontal line from point B. ### Step 2: Identify Angles and Distances From the top of the lighthouse (point A), the angle of depression to ship C is \(40^\circ\) and to ship D is \(30^\circ\). The height of the lighthouse (AB) is 80 m. ### Step 3: Use Trigonometry for Ship D (Angle 30°) In triangle ABD: - The angle of depression to ship D is \(30^\circ\). - Using the tangent function: \[ \tan(30^\circ) = \frac{AB}{BD} \] Where \(AB = 80\) m and \(BD\) is the distance from the base of the lighthouse to ship D. Since \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\): \[ \frac{1}{\sqrt{3}} = \frac{80}{BD} \] Rearranging gives: \[ BD = 80 \sqrt{3} \] Calculating \(BD\): \[ BD \approx 80 \times 1.732 = 138.56 \text{ m} \] ### Step 4: Use Trigonometry for Ship C (Angle 40°) In triangle ABC: - The angle of depression to ship C is \(40^\circ\). - Using the tangent function: \[ \tan(40^\circ) = \frac{AB}{BC} \] Where \(BC\) is the distance from the base of the lighthouse to ship C. Since \(\tan(40^\circ) \approx 0.8390\): \[ 0.8390 = \frac{80}{BC} \] Rearranging gives: \[ BC = \frac{80}{0.8390} \] Calculating \(BC\): \[ BC \approx 95.352 \text{ m} \] ### Step 5: Calculate the Distance Between the Two Ships The distance between the two ships (CD) is given by: \[ CD = BD - BC \] Substituting the values we found: \[ CD = 138.56 - 95.352 \approx 43.208 \text{ m} \] ### Step 6: Round to the Nearest Meter Rounding \(43.208\) to the nearest meter gives: \[ \text{Distance between the two ships} \approx 43 \text{ m} \] ### Final Answer The distance between the two ships is **43 meters**. ---
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ICSE-HEIGHTS AND DISTANCES -Exercise 22 C
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  6. A vertical tower is 20 m high. A man standing at some distance from th...

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  7. A man standing on the bank of a river observes that the angle of elev...

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  8. A man standing on the bank of a river observes that the angle of elev...

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  9. A 20 m high vertical pole and a vertical tower are on the same level g...

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  10. A 20 m high vertical pole and a vertical tower are on the same level g...

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  11. A vertical pole and a vertical tower are on the same level ground in ...

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  12. A vertical pole and a vertical tower are on the same level ground in ...

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  13. From a point 36 m above the surface of a lake , the angle of elevatio...

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  14. A man observes the angle of elevation of the top of a building to be 3...

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  15. As observed from the top of a 80 m tall lighthouse, the angle of dep...

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  16. In the given figure, A from the top of a building AB = 60 m high, the ...

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  17. In the figure given, from the top of a building AB = 60 m high, the an...

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  18. An aeroplane at an altitude of 250 m observes the angle of depression ...

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  19. The horizontal distance between two tower is 120 m. The angle of eleva...

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