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The ratio of the prices of two fans was ...

The ratio of the prices of two fans was `16: 23`. Two years later, when the price of the first fan had risen by 10% and that of the second by Rs 477, the ratio of their prices became `11: 20`. Find the original prices of the two fans.

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To find the original prices of the two fans, we can follow these steps: ### Step 1: Set up the initial prices based on the given ratio Let the original prices of the two fans be represented as: - Price of Fan 1 = 16x - Price of Fan 2 = 23x ### Step 2: Calculate the prices after 2 years After 2 years: - The price of Fan 1 increases by 10%. Therefore, the new price of Fan 1 becomes: \[ \text{New Price of Fan 1} = 16x + 0.1 \times 16x = 16x \times 1.1 = 17.6x \] - The price of Fan 2 increases by Rs 477. Therefore, the new price of Fan 2 becomes: \[ \text{New Price of Fan 2} = 23x + 477 \] ### Step 3: Set up the equation based on the new ratio According to the problem, after 2 years, the ratio of the prices of the two fans becomes 11:20. We can write this as: \[ \frac{17.6x}{23x + 477} = \frac{11}{20} \] ### Step 4: Cross-multiply to eliminate the fraction Cross-multiplying gives us: \[ 20 \times 17.6x = 11 \times (23x + 477) \] ### Step 5: Simplify the equation Expanding both sides: \[ 352x = 253x + 5247 \] ### Step 6: Solve for x Now, rearranging the equation: \[ 352x - 253x = 5247 \] \[ 99x = 5247 \] \[ x = \frac{5247}{99} = 53 \] ### Step 7: Find the original prices of the fans Now that we have the value of x, we can find the original prices: - Price of Fan 1: \[ 16x = 16 \times 53 = 848 \] - Price of Fan 2: \[ 23x = 23 \times 53 = 1219 \] ### Final Answer The original prices of the two fans are: - Price of Fan 1 = Rs 848 - Price of Fan 2 = Rs 1219 ---
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