Daya gets pocket money from his father every day. Out of the pocket money, he saves Rs 2.75 on first day, Rs 3.00 on second day, Rs 3.25 on third day and so on. Find:
the total amount saved by him in 30 days.

Answer

To find the total amount saved by Daya in 30 days, we can observe that the amounts he saves each day form an arithmetic progression (AP).

### Step-by-Step Solution:

1. **Identify the first term (A) and common difference (D):**
- The amount saved on the first day is Rs 2.75 (A = 2.75).
- The amount saved on the second day is Rs 3.00.
- The common difference (D) can be calculated as:
\[ D = 3.00 - 2.75 = 0.25 \]

2. **Determine the number of terms (N):**
- The total number of days is 30, so \( N = 30 \).

3. **Use the formula for the sum of the first N terms of an AP:**
- The formula for the sum \( S_N \) of the first N terms of an arithmetic progression is:
\[ S_N = \frac{N}{2} \times (2A + (N - 1)D) \]

4. **Substitute the values into the formula:**
- Substitute \( N = 30 \), \( A = 2.75 \), and \( D = 0.25 \):
\[ S_{30} = \frac{30}{2} \times \left(2 \times 2.75 + (30 - 1) \times 0.25\right) \]

5. **Calculate the components:**
- Calculate \( \frac{30}{2} = 15 \).
- Calculate \( 2 \times 2.75 = 5.5 \).
- Calculate \( 30 - 1 = 29 \) and then \( 29 \times 0.25 = 7.25 \).

6. **Combine the results:**
- Now, substitute back:
\[ S_{30} = 15 \times (5.5 + 7.25) \]
- Calculate \( 5.5 + 7.25 = 12.75 \).

7. **Final multiplication:**
- Now, calculate:
\[ S_{30} = 15 \times 12.75 = 191.25 \]

8. **Conclusion:**
- Therefore, the total amount saved by Daya in 30 days is Rs 191.25.