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A cummulative deposit account of monthly...

A cummulative deposit account of monthly instalment of 3,600 at 9% p.a. simple interest earns an interest of 17,982. Find the number of instalments paid.

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To solve the problem, we need to find the number of monthly installments paid into a cumulative deposit account that earns simple interest. Here’s how we can approach the solution step by step: ### Step 1: Understand the Problem We have a cumulative deposit account where: - Monthly installment (P) = 3,600 - Rate of interest (R) = 9% per annum - Total interest earned (SI) = 17,982 We need to find the number of installments (n). ### Step 2: Calculate the Simple Interest for One Month The formula for simple interest is given by: \[ SI = \frac{P \times R \times T}{100} \] Where: - \(P\) = Principal amount - \(R\) = Rate of interest - \(T\) = Time in years For one month, \(T = \frac{1}{12}\) years. Thus, we can substitute the values: \[ SI_{1 \text{ month}} = \frac{3600 \times 9 \times \frac{1}{12}}{100} \] ### Step 3: Simplify the Calculation Calculating the above expression: \[ SI_{1 \text{ month}} = \frac{3600 \times 9}{1200} = \frac{32400}{1200} = 27 \] So, the interest earned in the first month is 27. ### Step 4: Calculate Total Interest Earned Over n Months Since this is a cumulative deposit account, the interest for each month increases cumulatively. Thus, for n months, the total interest can be represented as: \[ SI_{total} = 27 \times (1 + 2 + 3 + ... + n) \] The sum of the first n natural numbers is given by: \[ \text{Sum} = \frac{n(n + 1)}{2} \] So, we can write: \[ SI_{total} = 27 \times \frac{n(n + 1)}{2} \] ### Step 5: Set Up the Equation We know that the total interest earned is 17,982, so we set up the equation: \[ 27 \times \frac{n(n + 1)}{2} = 17982 \] ### Step 6: Solve for n First, simplify the equation: \[ \frac{27n(n + 1)}{2} = 17982 \] Multiply both sides by 2: \[ 27n(n + 1) = 35964 \] Now, divide both sides by 27: \[ n(n + 1) = \frac{35964}{27} = 1332 \] This simplifies to: \[ n^2 + n - 1332 = 0 \] ### Step 7: Factor the Quadratic Equation We can factor the quadratic equation: \[ n^2 + n - 1332 = 0 \] To factor, we look for two numbers that multiply to -1332 and add to 1. The factors are: \[ (n - 36)(n + 37) = 0 \] Setting each factor to zero gives: \[ n - 36 = 0 \quad \text{or} \quad n + 37 = 0 \] Thus, \(n = 36\) or \(n = -37\). ### Step 8: Conclusion Since the number of installments cannot be negative, we take: \[ n = 36 \] Therefore, the number of installments paid is **36**.
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