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What number should be added to 27 x ^(3)...

What number should be added to `27 x ^(3) - 54 x ^(2) + 36 x - 11` so that resulting polynomial becomes divisible by `3x - 2` ?

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To solve the problem of finding the number that should be added to the polynomial \(27x^3 - 54x^2 + 36x - 11\) so that it becomes divisible by \(3x - 2\), we can follow these steps: ### Step 1: Identify the polynomial and the divisor Let the polynomial be: \[ f(x) = 27x^3 - 54x^2 + 36x - 11 \] We want to find a number \(c\) such that \(f(x) + c\) is divisible by \(3x - 2\). ### Step 2: Find the root of the divisor The divisor \(3x - 2\) can be set to zero to find its root: \[ 3x - 2 = 0 \implies x = \frac{2}{3} \] ### Step 3: Substitute the root into the polynomial We need to evaluate \(f\left(\frac{2}{3}\right) + c = 0\). First, calculate \(f\left(\frac{2}{3}\right)\): \[ f\left(\frac{2}{3}\right) = 27\left(\frac{2}{3}\right)^3 - 54\left(\frac{2}{3}\right)^2 + 36\left(\frac{2}{3}\right) - 11 \] ### Step 4: Calculate each term Calculate each term separately: 1. \(27\left(\frac{2}{3}\right)^3 = 27 \cdot \frac{8}{27} = 8\) 2. \(-54\left(\frac{2}{3}\right)^2 = -54 \cdot \frac{4}{9} = -24\) 3. \(36\left(\frac{2}{3}\right) = 36 \cdot \frac{2}{3} = 24\) 4. The constant term is \(-11\). Now, substitute these values back into the polynomial: \[ f\left(\frac{2}{3}\right) = 8 - 24 + 24 - 11 \] ### Step 5: Simplify the expression Combine the terms: \[ f\left(\frac{2}{3}\right) = 8 - 24 + 24 - 11 = 8 - 11 = -3 \] ### Step 6: Set up the equation Now we have: \[ f\left(\frac{2}{3}\right) + c = 0 \implies -3 + c = 0 \] ### Step 7: Solve for \(c\) Solving for \(c\): \[ c = 3 \] ### Final Answer The number that should be added is: \[ \boxed{3} \]
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ICSE-REVISION PAPER -5-SECTION B
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