Prove that the locus of a point equidistant from the extermities of a line segment is the perpendicular bisector if it.

Prove that the locus of a point that is equidistant from both axis is y=x.

Statement-1: The locus of point z satisfying |(3z+i)/(2z+3+4i)|=3/2 is a straight line. Statement-2 : The locus of a point equidistant from two fixed points is a straight line representing the perpendicular bisector of the segment joining the given points.

Statement-1: If z is a complex number satisfying (z-1)^(n) , n in N , then the locus of z is a straight line parallel to imaginary axis. Statement-2: The locus of a point equidistant from two given points is the perpendicular bisector of the line segment joining them.

Statement - 1 : If the perpendicular bisector of the line segment joining points A (a,3) and B( 1,4) has y-intercept -4 , then a = pm 4 . Statement- 2 : Locus of a point equidistant from two given points is the perpendicular bisector of the line joining the given points .

Find the locus of a point equidistant from the point (2,4) and the y-axis.

Find the locus of a point equidistant from the point (2,4) and the y-axis.

AB is a line-segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B. Show that the line PQ is the perpendicular bisector of AB

Show that the locus of a point equidistant from a fixed point is a circle with the fixed point as centre.

Statement 1: Each point on the line y-x+12=0 is equidistant from the lines 4y+3x-12=0,3y+4x-24=0 Statement 2: The locus of a point which is equidistant from two given lines is the angular bisector of the two lines.

Draw a line segment PQ=4.8 cm. Construct the perpendicular bisector of PQ.