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From a point of observation at the top of a 175 m high cliff, the angles of depression of two objects are `x ^(@) and y ^(@)` such that ` tan x ^(@) = 2.5 and tan y ^(@) =1.4.` If the point of observation and the two objects are long the same straight line, find the distance betwen the two objects if they are on the :
same side of the cliff

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To solve the problem step by step, we will follow these steps: ### Step 1: Understand the Problem We have a cliff of height 175 m. From the top of the cliff, we are given two angles of depression, \( x^\circ \) and \( y^\circ \), with their respective tangents: - \( \tan x^\circ = 2.5 \) - \( \tan y^\circ = 1.4 \) We need to find the distance between two objects, C and D, located at the angles of depression \( x^\circ \) and \( y^\circ \) respectively. ### Step 2: Identify the Right Triangles Let: - Point A be the top of the cliff. - Point B be the base of the cliff directly below A. - Point C be the position of the first object at angle \( x^\circ \). - Point D be the position of the second object at angle \( y^\circ \). ### Step 3: Set Up the Right Triangles In triangle ABC: - \( AB = 175 \) m (height of the cliff) - \( BC \) is the horizontal distance from the base of the cliff to object C. Using the tangent function: \[ \tan x^\circ = \frac{AB}{BC} \implies BC = \frac{AB}{\tan x^\circ} = \frac{175}{2.5} \] ### Step 4: Calculate \( BC \) Calculating \( BC \): \[ BC = \frac{175}{2.5} = \frac{1750}{25} = 70 \text{ m} \] ### Step 5: Set Up the Second Right Triangle In triangle ADB: - \( AD = 175 \) m (same height) - \( BD \) is the horizontal distance from the base of the cliff to object D. Using the tangent function: \[ \tan y^\circ = \frac{AB}{BD} \implies BD = \frac{AB}{\tan y^\circ} = \frac{175}{1.4} \] ### Step 6: Calculate \( BD \) Calculating \( BD \): \[ BD = \frac{175}{1.4} = \frac{1750}{14} = 125 \text{ m} \] ### Step 7: Find the Distance Between Objects C and D The distance \( DC \) between the two objects can be found by subtracting \( BC \) from \( BD \): \[ DC = BD - BC = 125 - 70 = 55 \text{ m} \] ### Final Answer The distance between the two objects is **55 meters**. ---
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From a point of observation at the top of a 175 m high cliff, the angles of depression of two objects are x ^(@) and y ^(@) such that tan x ^(@) = 2.5 and tan y ^(@) =1.4. If the point of observation and the two objects are long the same straight line, find the distance betwen the two objects if they are on the : opposite sides of the cliff.

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