`{:(" 9 8"),("+4 A"),(--),("CB3"),(--):}`

Answer

To solve the problem step by step, we need to add the numbers given in the question and find the values of A, B, and C.

### Step-by-Step Solution:

1. **Understand the Addition**: We have the addition problem:
\[ 98 + 4A = CB3 \]
Here, \(CB3\) represents a three-digit number where C is the hundreds place, B is the tens place, and 3 is the units place.

2. **Analyze the Units Place**:
- The units digit of the sum is 3.
- When we add the units digits of 98 (which is 8) and \(4A\) (which is A), we need to find a value for A such that:
\[ 8 + A = 3 \text{ or } 13 \text{ (if we carry over 1)} \]
- Since 8 + A cannot equal 3 (as it would require A to be negative), we consider the case where we carry over 1. Thus:
\[ 8 + A + 1 = 13 \]
- Simplifying gives:
\[ A = 13 - 9 = 4 \]

3. **Update the Addition**: Now that we have A = 5, we can rewrite the addition:
\[ 98 + 45 = CB3 \]

4. **Perform the Addition**:
- Now we add 98 and 45:
\[ 98 + 45 = 143 \]

5. **Identify C and B**: Now we can compare the result 143 with CB3:
- Here, C = 1, B = 4, and the units digit is 3.

6. **Final Values**:
- Therefore, we have:
\[ A = 5, B = 4, C = 1 \]

### Summary of Results:
- A = 5
- B = 4
- C = 1