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31x5 divisible by 3 ?...

`31x5` divisible by 3 ?

A

`0, 3, 6` or `9`

B

`0, 4, 8` or `7`

C

`1, 3, 5` or `7`

D

`2, 4, 6` or `8`

Text Solution

AI Generated Solution

The correct Answer is:
To determine if the number \( 31x5 \) is divisible by 3, we can use the divisibility rule for 3, which states that a number is divisible by 3 if the sum of its digits is divisible by 3. ### Step-by-Step Solution: 1. **Identify the digits of the number**: The number is \( 31x5 \). The digits are 3, 1, \( x \), and 5. 2. **Calculate the sum of the digits**: \[ \text{Sum} = 3 + 1 + x + 5 \] Simplifying this gives: \[ \text{Sum} = 9 + x \] 3. **Check divisibility by 3**: For \( 31x5 \) to be divisible by 3, the sum \( 9 + x \) must be divisible by 3. 4. **Evaluate possible values for \( x \)**: - Since \( 9 \) is already divisible by 3, we need to find values of \( x \) such that \( 9 + x \) is also divisible by 3. - We can check values of \( x \) from 0 to 9. 5. **Testing values of \( x \)**: - If \( x = 0 \): \( 9 + 0 = 9 \) (divisible by 3) - If \( x = 1 \): \( 9 + 1 = 10 \) (not divisible by 3) - If \( x = 2 \): \( 9 + 2 = 11 \) (not divisible by 3) - If \( x = 3 \): \( 9 + 3 = 12 \) (divisible by 3) - If \( x = 4 \): \( 9 + 4 = 13 \) (not divisible by 3) - If \( x = 5 \): \( 9 + 5 = 14 \) (not divisible by 3) - If \( x = 6 \): \( 9 + 6 = 15 \) (divisible by 3) - If \( x = 7 \): \( 9 + 7 = 16 \) (not divisible by 3) - If \( x = 8 \): \( 9 + 8 = 17 \) (not divisible by 3) - If \( x = 9 \): \( 9 + 9 = 18 \) (divisible by 3) 6. **List the valid values of \( x \)**: The values of \( x \) that make \( 31x5 \) divisible by 3 are \( 0, 3, 6, \) and \( 9 \). ### Conclusion: The values of \( x \) for which \( 31x5 \) is divisible by 3 are \( 0, 3, 6, \) and \( 9 \).
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