Home
Class 8
MATHS
{x : 4-2x gt -6, x in Z}...

`{x : 4-2x gt -6, x in Z}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the inequality \(4 - 2x > -6\) where \(x\) is an integer, we will follow these steps: ### Step 1: Rewrite the inequality Start with the original inequality: \[ 4 - 2x > -6 \] ### Step 2: Move terms around Add \(2x\) to both sides of the inequality to isolate the variable on one side: \[ 4 > -6 + 2x \] ### Step 3: Simplify the right side Now, add \(6\) to both sides: \[ 4 + 6 > 2x \] This simplifies to: \[ 10 > 2x \] ### Step 4: Divide by 2 Now, divide both sides by \(2\) to solve for \(x\): \[ 5 > x \] or equivalently, \[ x < 5 \] ### Step 5: Identify the set of integers Since \(x\) must be an integer, the integers that satisfy \(x < 5\) are: \[ \{..., -3, -2, -1, 0, 1, 2, 3, 4\} \] ### Final Set Thus, the set of integers \(x\) that satisfy the inequality \(4 - 2x > -6\) is: \[ \{x \in \mathbb{Z} : x < 5\} = \{..., -3, -2, -1, 0, 1, 2, 3, 4\} \]
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Solve -5(x+4) gt 30, x in Z

Solve , 4x-5 gt 10-x, x in {0,1,2,3,4,5,6,7}

2x - 3y gt 6

If A=(x:x= 4n,nin Z) and b={x:x = 6n,n in Z}, then A capB contains

The area (in sq units) of the region {(x, y) : y^2 gt= 2x and x^2 + y^2 lt= 4x, x gt= 0, y gt= 0} is

Let tanx-tan^2x >0 and |2sinx| x > npi,n in Z (b) x > npi-pi/6,n in Z x

3x - 7 gt 2 ( x - 6 ), 6 - x gt 11 - 2x

If x gt y gt z gt 0 , then find the value of "cot"^(-1) (xy + 1)/(x - y) + cot^(-1).(yz + 1)/(y - z) + cot^(-1).(zx + 1)/(z - x)

If 7x + 6y - 2z = 0, 3x + 4y + 2z = 0, x - 2y - 6z = 0 then which option is correct

If x is an integer satisfying x^(2)-6x+5 le 0 " and " x^(2)-2x gt 0 , then the number of possible values of x, is