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Given, universal set ={x in Z: -6 lt x l...

Given, universal set =`{x in Z: -6 lt x le 6}`, N={n:n is a non-negative number} and P={x:x ia a non-positive number}. Find:
(i) N', (ii) P'

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The correct Answer is:
To solve the problem, we need to find the complements of the sets N and P with respect to the universal set U. ### Step 1: Define the Universal Set U The universal set is defined as: \[ U = \{ x \in \mathbb{Z} : -6 < x \leq 6 \} \] This means U includes all integers from -5 to 6. Therefore, we can list the elements of U: \[ U = \{-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6\} \] ### Step 2: Define the Set N Set N is defined as: \[ N = \{ n : n \text{ is a non-negative number} \} \] In the context of the universal set, the non-negative integers from U are: \[ N = \{0, 1, 2, 3, 4, 5, 6\} \] ### Step 3: Find the Complement of Set N (N') The complement of set N, denoted as N', is defined as: \[ N' = U - N \] This means we will take all elements from U and remove those that are in N: \[ N' = \{-5, -4, -3, -2, -1\} \] ### Step 4: Define the Set P Set P is defined as: \[ P = \{ x : x \text{ is a non-positive number} \} \] In the context of the universal set, the non-positive integers from U are: \[ P = \{0, -1, -2, -3, -4, -5\} \] ### Step 5: Find the Complement of Set P (P') The complement of set P, denoted as P', is defined as: \[ P' = U - P \] This means we will take all elements from U and remove those that are in P: \[ P' = \{1, 2, 3, 4, 5, 6\} \] ### Final Answers (i) \( N' = \{-5, -4, -3, -2, -1\} \) (ii) \( P' = \{1, 2, 3, 4, 5, 6\} \) ---
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