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3 men and 4 boys can complete a certain ...

3 men and 4 boys can complete a certain amount of work in 28 days, whereas 4 men and 6 boys can complete the same work in 20 days. Find :
The number of days required by 7 men and 6 boys to complete the same work.

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To solve the problem step by step, we will use the information given about the work done by men and boys to find out how many days 7 men and 6 boys would take to complete the same work. ### Step 1: Establish the Work Equations We know that: - 3 men and 4 boys can complete the work in 28 days. - 4 men and 6 boys can complete the same work in 20 days. Using the formula: \[ \text{Work} = \text{Efficiency} \times \text{Time} \] We can set up the equations based on the information provided. For the first scenario: \[ (3M + 4B) \times 28 = W \] For the second scenario: \[ (4M + 6B) \times 20 = W \] ### Step 2: Equate the Work Done Since both expressions equal the same work \( W \), we can set them equal to each other: \[ (3M + 4B) \times 28 = (4M + 6B) \times 20 \] ### Step 3: Expand and Simplify Expanding both sides: \[ 84M + 112B = 80M + 120B \] Now, rearranging the equation: \[ 84M - 80M = 120B - 112B \] \[ 4M = 8B \] ### Step 4: Find the Relationship Between Men and Boys From the equation \( 4M = 8B \), we can simplify it to find the relationship: \[ M = 2B \] This means 1 man is equivalent to 2 boys. ### Step 5: Substitute the Relationship Now, we need to find the efficiency of 7 men and 6 boys. We can express the boys in terms of men: \[ 6B = 3M \] So, the total efficiency of 7 men and 6 boys can be expressed as: \[ 7M + 3M = 10M \] ### Step 6: Set Up the Work Equation for 7 Men and 6 Boys Now we can use the efficiency to find out how many days \( x \) it will take for 7 men and 6 boys to complete the work: \[ 10M \times x = W \] ### Step 7: Use the Work from One of the Previous Equations We can use the work done by 3 men and 4 boys: \[ W = (3M + 4B) \times 28 \] Substituting \( B = \frac{M}{2} \): \[ W = (3M + 4 \times \frac{M}{2}) \times 28 \] \[ W = (3M + 2M) \times 28 \] \[ W = 5M \times 28 \] \[ W = 140M \] ### Step 8: Set the Equations Equal Now we can set the two expressions for work equal: \[ 10M \times x = 140M \] ### Step 9: Solve for \( x \) Dividing both sides by \( 10M \): \[ x = \frac{140M}{10M} \] \[ x = 14 \] ### Final Answer The number of days required by 7 men and 6 boys to complete the same work is **14 days**. ---
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ICSE-DIRECT AND INVERSE VARIATIONS-EXERCISE 10 (E)
  1. 3 men and 4 boys can complete a certain amount of work in 28 days, whe...

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  2. A can do a piece of work in 10 days and B in 15 days. How long will th...

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  3. A and B together can do a piece of work in 6(2)/(3) days, but B along ...

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  4. A can do a work in 15 days and B in 20 days. If they work together on ...

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  5. A, B and C can do a piece of work in 6 days, 12 days and 24 days resp...

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  6. A and B working together can mow a field in 56 days and with the help ...

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  7. A can do a piece of work in 24 days, A and B can do it in 16 days and ...

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  8. A can do a piece of work in 20 days and B in 15 days. They worked toge...

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  9. A can finish a piece of work in 15 days and B can do it in 10 days. Th...

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  10. A can do a piece of work in 10 days, B in 18 days and A, B and C toget...

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  11. A can do (1)/(4) of a work in 5 days and B can do (1)/(3) of the same ...

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  12. One tap can fill a cistern in 3 hours and the waste pipe can empty the...

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  13. A and B can do a work in 8 days, B and C in 12 days, and A and C in 16...

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  14. A and B complete a piece of work in 24 days, B and C do the same work ...

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  15. A and B complete a piece of work in 24 days, B and C do the same work ...

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  16. A and B complete a piece of work in 24 days, B and C do the same work ...

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  17. A and B can do a piece of work in 40 days, B and C in 30 days, and C a...

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  18. A and B can do a piece of work in 40 days, B and C in 30 days, and C a...

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  19. A can do a piece of work in 10 days, B in 12 days and C in 15 days. Al...

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  20. Two pipes P and Q would fill an empty cistern in 24 minutes and 32 min...

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