Separate 178 into two parts so that the first part is 8 less than twice the second part.

Answer

To solve the problem of separating 178 into two parts such that the first part is 8 less than twice the second part, we can follow these steps:

### Step 1: Define the Variables
Let the first part be \( x \). Then, the second part can be expressed as:
\[ \text{Second part} = 178 - x \]

### Step 2: Set Up the Equation
According to the problem, the first part \( x \) is 8 less than twice the second part. This can be written as:
\[ x = 2(178 - x) - 8 \]

### Step 3: Simplify the Equation
Now, let's simplify the equation:
\[ x = 2(178) - 2x - 8 \]
\[ x = 356 - 2x - 8 \]
\[ x = 348 - 2x \]

### Step 4: Combine Like Terms
To isolate \( x \), we can add \( 2x \) to both sides:
\[ x + 2x = 348 \]
\[ 3x = 348 \]

### Step 5: Solve for \( x \)
Now, divide both sides by 3:
\[ x = \frac{348}{3} = 116 \]

### Step 6: Find the Second Part
Now that we have \( x \), which is the first part, we can find the second part:
\[ \text{Second part} = 178 - x = 178 - 116 = 62 \]

### Final Answer
Thus, the two parts are:
- First part: \( 116 \)
- Second part: \( 62 \)