1 ml of glacial acetic acid and 1 ml of ethanol are mixed together in a test tube. Few drops of concentrated sulphuric acid is added to the mixture and warmed in a water bath for 5min.answer the question: Name the resultant compound formed.

1 ml of glacial acetic acid and 1 ml of ethanol are mixed together in a test tube. Few drops of concentrated sulphuric acid is added to the mixture and warmed in a water bath for 5min.answer the question:What are the special characteristics of the compound formed?

1 ml of glacial acetic acid and 1 ml of ethanol are mixed together in a test tube. Few drops of concentrated sulphuric acid is added to the mixture and warmed in a water bath for 5min.answer the question:What name is given to such a reaction?

1 ml glacial acetic acid and 1 ml of ethanol are mixed together in a test tube. Few drops of concentrated sulphuric acid is added to the mixture and warmed in a water bath for 5 min. Represent the above change by a chemical equation.

Amount of 5 ml each of acetic acid and water are mixed together and shaken well The resulting mixture would appear as in

If 2ml of acetic acid was added slowly in drops to 5ml of water then we will notice

Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as : CH_(3)COOH(I)+C_(2)H_(5)OH(I) hArrCH_(3)COOC_(2)H_(5)(I)+H_(2)O(I) (i) Write the concentration ratio (reaction quotient). Q_(c) , for this reaction (note : water is not in excess and is not a solvent in this reaction ) (ii) At 293K , if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant. (iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293K , 0.214 mol of ethyl acetate is found after sometime. Has equilibrium been reached ?

The ammonia evolved by the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 ml of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M solution hydroxide solution for complete neutralization. The organic compound is