Plot each pair of points, join them by straight line segments: (-2, 1), (2, 1),(-2, 1), (-4, 0), (4, 0), (2, 1), (4, 0), (2, 3),(2, 1), (2, 3),(2, 3), (-2, 3)(2, 3), (-2, 3),(-2, 3), (-4, 0),(-2, 1), (-2, 3).

In a graph Sheet Plot each pair of points, join them by line segments (i) (2,5), (4,7) (ii) (-3, 5), (-1, 7) (iii) (-3, -4), (2,-4) (iv) (-3, -5), (2, -5) (v) (4,-2), (4,-3) (vi) (-2,4), (-2,3) (vii) (-2, 1), (-2,0) Now join the following pairs of points by straight line segments, in the same graph. (viii) (-3,5), (-3,4) (ix) (2,5), (2,-4) (x) (2,-4),(4,-2) (xi) (2,-4), (4,-3) (xii) (4,-2), (4,7) (xiii) (4,7), (-1, 7) (xiv) (-3,2), (2,2) Now you will get a surprise figure. What is it?

The coplanar points (1,2,4 ),(-2,2,1 ), (2,4,-3 ) ,(5,4,0) form

Which of the following points lie on the axes?Also name them? : (4,-5), (3, 0), (-4, 0). (-1, -3) (-2, 3), (-2.5, 0).(0, -4), (2, 3), (0, -3.5) , (-3, 0), (0, -5), (3.5, 2.5).

The midpoint of the line segment joining (2,3,-1 ), (4,5,3,) is

If A=[(1,0,2),(0,1,2),(1,2,0)],B=[(1,-2,3),(2,3,-1),(-3,1,2)] then

If A=[(1,3,0),(-1,2,1),(0,0,2)],B=[(2,3,4),(1,2,3),(-1,1,2)] then AB=

Locate the points (0, 0), (1, 1), (2, 2), (3, 3) (4,4), (-1, -1), (-2,-2), (-3, -3), (-4,-4) and what is your observation?

The coplanar points (1,2,2 ) ,(2,-1 , 0) ,(1,1,3 ),(0,4,5, ) from a

If A=[(1,-2,3),(-4,2,5)],B=[(1,3),(-1,0),(2,4)] then 2A+3B'=

Find the product [{:(2,2,1),(1,0,2),(2,1,2):}][{:(-2,-3,4),(2,2,-3),(1,2,-2):}]