In the adjacent figure `DeltaABC, D` is the midpoint of BC. `DE_|_AB, DF_|_AC` and `DE = DF`. Show that `DeltaBED ~= Delta CFD`.

In the adjacent figure, we have AC = XD, C and D are mid points of AB and XY respectively. Show that AB = XY.

ABCD is a parallelogram DE _|_ AB, DF_|_BC . Find DF.

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the following figure DE||BC . Find AD.

In the following figure DE||BC . Find EC.

In the adjacent figure ABCD is a parallelogram and E is the midpoint of the side BC. If DE and AB are produced to meet at F, show that AF=2AB .

In the adjacent figure ABCD is a parallelogram and E is the midpoint of the side BC. If DE and AB are produced to meet at F, show that AF = 2AB .

In the adjacent figure DeltaABC and DeltaDBC are two triangles such that bar(AB) = bar(BD) and bar(AC) = bar(CD) . Show that DeltaABC ~= DeltaDBC.

In the following figure, DE//BC then x =

In the following figures DE||BC. Find AD