The velocity of a particle moving in the positive direction of x-axis veries as `v=10sqrtx`. Assuming that at `t=0`, particle was at `x=0`

The velocity of a particle moving in the positive direction of X-axis varies as v=5sqrt(x) . Assuming that at t = 0, particle was at x = 0. What is the acceleration of the particle ?

The velocity of a particle moving in the positive direction of x -axis varies as v = alpha sqrt(x) where alpha is positive constant. Assuming that at the moment t = 0 , the particle was located at x = 0 , find (i) the time dependance of the velocity and the acceleration of the particle and (ii) the mean velocity of the particle averaged over the time that the particle takes to cover first s meters of the path.

The velocity of a particle moving in the positive direction of the x axis varies as v=alphasqrtx , where alpha is a positive constant. Assuming that at the moment t=0 the particle was located at the point x=0 , find: (a) the time dependence of the velocity and the acceleration of the particle, (b) the mean velocity of the particle averaged over the time that the particle takes to cover the first s metres of the path.

The velocity of a particle moving in the positive direction of the X-axis varies as V=Ksqrt(S) where K is a positive constant. Draw V-t graph.

The velocity of a particle moving in the x direction varies as V = alpha sqrt(x) where alpha is a constant. Assuming that at the moment t = 0 the particle was located at the point x = 0 . Find the acceleration.

A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity that varies as v=psqrtx . The displacement of the particle varies with time as (where, p is constant)

v_(x) is the velocity of a particle moving along the x-axis as shown in the figure. If x=2.0m at t=1.0s, what is the position of the particle at t=6.0s ?

Velocity of particle moving along positive x-direction is v = (40-10t)m//s . Here,t is in seconds. At time t=0, tha x coordinate of particle is zero. Find the time when the particle is at a distance of 60 m from origin.

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.