A ball is projected upwards from the top of a tower with a velocity `50ms^-1` making an angle `30^@` with the horizontal. The height of tower is 70m. After how many seconds from the instant of throwing, will the ball reach the ground. `(g=10 ms^-2)`

A ball is projected horizontal from the top of a tower with a velocity v_(0) . It will be moving at an angle of 60^(@) with the horizontal after time.

A ball is thrown with velocity 40 m//s at angle 30^(@) with horizontal from the top of a tower of height 60 m . At what horizontal distance from the foot of tower, the ball will strike the gorund ?

A ball is thrown from the top of tower with an initial velocity of 10ms^(-1) at an angle of 30^(@) with the horizontal. If it hits the ground of a distance of 17.3m from the back of the tower, the height of the tower is (Take g=10ms^(-2))

A ball is thrown from the top of a tower of 61 m high with a velocity 24.4 ms^(-1) at an elevation of 30^(@) above the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground?

A ball is thrown from the ground with a velocity of 20sqrt3 m/s making an angle of 60^@ with the horizontal. The ball will be at a height of 40 m from the ground after a time t equal to (g=10 ms^(-2))

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

An object is thrown towards the tower which is at a horizontal distance of 50 m with an initial velocity of 10 ms^(-1) and making an angle 30^(@) with the horizontal. The object hits the tower at certain height. The height from the bottom of the tower, where the object hits the tower is (Take, g = 10 ms^(-2))

A ball is thrown from the top of a 35m high tower with initial velocity of magnitude u=80" ms"^(-1) at an angle 25^(@) with horizontal. Find the time to reach the ground and the horizontal distance covered by the ball.