If the normal to the ellipse `x^2/25+y^2/1=1` is at a distance p from the origin then the maximum value of p is

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

Number of points on the ellipse x^2/25+y^2/7=1 whose distance from the centre of the ellipse is 2sqrt7 is

A point P on the ellipse (x^(2))/(2)+(y^(2))/(1)=1 is at distance of sqrt(2) from its focus s. the ratio of its distance from the directrics of the ellipse is

If CF is perpendicular from the centre of the ellipse x^2/25+y^2/9=1 to the tangent at P, G is the point where the normal at P meets the major axis, then CF. PG =

P_(1) and P_(2) are corresponding points on the ellipse (x^(2))/(16)+(y^(2))/(9)=1 and its auxiliary circle respectively. If the normal at P_(1) to the ellipse meets OP_(2) in Q (where O is the origin), then the length of OQ is equal to

If from a point P(0,alpha), two normals other than the axes are drawn to the ellipse (x^(2))/(25)+(y^(2))/(16)=1, such that | alpha|

Suppose S and S' are foci of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 . If P is a variable point on the ellipse and if Delta is the area (in sq. units) of the triangle PSS' then the maximum value of Delta is double of

If the perpendicular distance of a point A other than the origin from the plane x+y+z=p is equal to the distance of the plane from the origin,then the coordinates of p are (A) (p,2p,0)(B)(0,2p,-p)(C)(2p,p,-p)(D)(2p,-p,2p)