The velocity of a particle is v=v_(0)+gt+ft^(2) .If its position is x=0 at t=0, then its displacement after 1s is

The velocity of a particle is v = v_(0) + gt + ft^(2) . If its position is x=0 at t= 0 , then its displacement after unit time ( t = 1 ) is

The velocity of particle is v=v_(0)+"gt"+ft^(2) . If its position is x=0 at t=0 then its displacement after unit time (t=1) is

The velocity of a particle is v=v_(0)+g t+Ft^(2) . Its position is x=0 at t=0, then its displacement after time (t=1) is :

The velocity of a particle is v = v_0 + g t + ft^2 . If its position is x = 0 at t = 0 , then its displacement after unit time (t = 1) is.

The velocity of a particle is given by v=u_(0) + g t+ 1/2 at^(2) . If its position is x =0 at t=0 , then what is its displacement after t=1 s ?

If velocity of a particle is given by v=3t^(2)-6t +4 . Find its displacement from t=0 to 3 secs .

If velocity of a moving particle in is v= a + g t + ft^2 (a,g,f are constants). At t=0 body is at origin. Find displacement after t=1s.

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

The acceleration of a particle is given by a = 3t and at t = 0, v = 0, x = 0. The velocity and displacement at t = 2 sec will be-

A particle is performing SHM aong x-axis,such that its velocity is v_1 when its displacement from mean position is x_1 and v_2 when its displacement from mean position is x_2 .Time period of oscillation is