If X is the a random variable with probability mass function `P(x) = kx `, for x = 1,2,3
= 0 , otherwise
then k = ……..

Let X is a continuous random variable with probability density function f(x)={{:(x/6+k,0lexle3),(0," otherwise"):} The value of k is equal to

Let the p.m.f. of a random variable X be - P(x) = (3 -x)/10 " for " x = - 1, 0, 1, 2 = 0 otherwise Then E(X) is ………… .

Find expected value of the random Variable X whose probability mass function is X=x,1,2,3 P(X=x) 1/5,2/5,2/5

X is continuous random variable with probability density function f(x)=(x^(2))/(8),0 le x le 1 . Then, the value of P(0.2leXle0.5) is

If the probability mass function of a discrete random variable X is P(x)=C/(x^3), x=1,2,3 =0, otherwise Then E(X)=

A random variable 'X' has a probability distribution P(X) of the following form (k is constant): then k = __________ .

If the p.d.f of a continuous random variable X is f(x)=kx^(2)(1-x), 0 lt x lt 1 = 0 otherwise Then the value of k is

The random variable X has a probability distribution P(X) of the following form, where k is some number : P(X) = {(k ,if x=0) , (2k ,if x=1), (3k ,if x=2), (0 otherwise) (a) Determine k. (b) Find P ( X lt 2) , P ( X le 2) , P (X ge 2 )