(3) `int(x^(2)-5x+6)/(x-3)dx`

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(3) int(x^(2)+5x+6)dx

" (1) "int(x^(2)+5x+6)/((x+2))dx

int(x^(2))/((x^(2)+6x-3))dx

int(x^2-3)/(x^3-7x+6)dx

Evaluate: (i) int(x^(2)+x+5)/(3x+2)dx (ii) int(2x+3)/((x-1)^(2))dx

int(x^(2))/(x^(2)-5x+6)dx=

int 1/(x^2-5x+6) dx

int(5x+6)/(2x+3)dx

int(e^(2-5x)+(2)/(6x+1))dx=

int(5x+2)/((x-2)(x-3))dx