A cricket ball of mass 100g has initial velocity `vec u = (3hati + 4hatj)ms` and final velocity `vec v = (-3hati -4hatj)ms` after being hit by the bat.The magnitude of the impulse on the bat by the ball will be

A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 hatj)ms^(-1) and a final velocity v = -(3hati + 4 hatj) ms^(-1) , after being hit. The change in momentum (final momentum - initial momentum ) is (in Kg ms^(1) )

A cricket ball of mass 150 g has an initial velocity bar(u)=(3hati-4hatj)ms^(-1) and a final velocity bar(v)=-(3hati-4hatj)ms^(-1) after being hit. The change in momentum (final momentum -initial momentum) is ("in kg ms"^(-1))

A cricket ball of mass 150g has an initial velocity (3 hati + 4hatj)ms^(-1) and a final velocity upsilon = -(3hati + 4hatj)ms^(-1) after beigh hit The change in momentum (final momentum initial momentum) is (in kg ms^(-1) )

A body of mass 0.8 kg has intial velocity (3hati-4hatj) ms^(-1) and final velocity (-6hatj+2hatk) ms^(-1) . Find change in kinetic energy of the body?

A small sphere of mass m =2kg moving with a velocity baru = 4hati - 7hatj m//s colides with a smooth wall and returns with a velocity barv = -hati + 3hatj m//s . The magnitude of the impulse received by the ball is .

A particle has an initial velocity of 3hati + 4hatj and on acceleration of 0.4hatj + 0.3hatj . The magnitude of its velocity after 10 s is

A particle has an initial velocity of 3hati+ 4hatj and an acceleration of 0.4hati +0.3hatj Its speed after 10 s is

A particular has initial velocity , v=3hati+3hatj and a constant force F=4hati-3hatj acts on it. The path of the particle is