If `sectheta=m, tantheta = n`, then `1/m{(m+n)+1/(m+n)}`

If sec theta=m,tan theta=n, then (1)/(m){(m+n)+(1)/(m+n)}]}

If sectheta + tantheta = m, show that : sin theta = (m^(2) - 1 )/(m^(2) + 1)

If tantheta+sintheta=m and tantheta-sintheta=n , then prove that: m^(2)-n^(2)=4sqrt(mn)

If tantheta+sintheta=m and tantheta-sintheta=n , then the value of m^2-n^2 is equal to (a)4 mn (b) 2sqrt(mn) (c) 4sqrt(mn) (d) 2sqrt(m//n)

If tantheta +sintheta = m and tantheta-sintheta=n , then prove that m^(2)-n^(2)=4sinthetatantheta .

If m, n in N , then l_(m n) = int_(0)^(1) x^(m) (1-x)^(n) dx is equal to

If (a^m)^n=a^m.a^n then find the value of m(n-1)-(n-1)