Electronegativity values of some elements are given. Analysing these values, find whether the follwing compounds are ionic or covalent. (Electronegativity of Ca=1.0, O=3.5, C=2.5, S=2.58, H=2.2, F=3.98)
a) Sulphur dioxide (`SO_2`)
b) Water (`H_2O`)
c) Calcium fluoride (`CaF_2`)
d) Carbon dioxide (`CO_2`)

Explanation

a)Covalent bond (Electronegativity difference between sulphur and oxygen = 3.5-2.58 = 0.92)
b)Covalent bond (ELectronegativity difference between hydrogen and oxygen = 3.5-2.2 = 1.3)
c)Ionic bond (Electronegativity difference between calcium and fluoride = 3.98-1.0 = 2.98)
d) Covalent bond (ELevtronegativity difference between sulphur and oxygen = 3.5-2.5=1.0)