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2 Na^x + Cl2^0 rarr 2 Na^y Cl^(-1) a)...

`2 Na^x + Cl_2^0 rarr 2 Na^y Cl^(-1)`
a) Find out x and y.
b) Write the equation of reduction reaction.
c) Which is the reducing agent in this reaction.

Text Solution

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a) x =0, y= +1
b) .Cl + 1e^- rarr Cl^-.
c) Na
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