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Fe^0 + 2HCl^(-1) rarr FeCl2^(-1) + H2 ^0...

`Fe^0 + 2HCl^(-1) rarr FeCl_2^(-1) + H_2 ^0`
a) Find the oxidising state of Fe in `FeCl_2` and H in` HCl`.
b) Identify the oxidising agent and reducing agent in the given equation.

Text Solution

Verified by Experts

a) Oxidation state of Fe in .FeCl_2. = +2, H in HCl is +1
b) Oxidising agent - HCl/ .H^+.
Reducing agent - Fe
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