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Zn^0 + Cu^(2+) (SO4)2^(2-) rarr Zn^(2+) ...

`Zn^0 + Cu^(2+) (SO_4)_2^(2-) rarr Zn^(2+) (SO_4)_2^(2-) + Cu^0`
Analyse the the given equation and answer the following questions:
a) Which element gets oxidised?
b) Which ion gets reduced?
c) Which is the oxidising agent?
d) Which is reducing agent?

Text Solution

Verified by Experts

a) Zn
b) ion - .Cu/Cu^(2+).
c) .CuSO_4/Cu^(2+).
d) Zn
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