Calculate the following with respect to 112L of `CO_2` kept at STP.
a. Find out the number of moles in the given volume.
b. Find out the mass of `CO_2` in the given amount of gas.

Explanation

No. of moles
= (volume in litre/22.4L)
(112L/22.4L) = 5 moles
b. molecular mass of `CO_2`
= `(1 xx C) + (2 xx O)`
=`(1 xx 12) + (2 xx 16) = 44
Mass of 1 mole of `CO_2` = 44g
Mass of 5 moles (112L) `CO_2` = 44g
= `44 xx 5` = 220g