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The ionic size of Na^+, Mg^(2+), Al^(3+)...

The ionic size of `Na^+`, `Mg^(2+)`, `Al^(3+)` and `Si^(4+)` follows the order: `Na^+ltMg^(2+)ltAl^(3+)ltSi^(4+)`, `Na^+gtMg^(2+)gtAl^(3+)gtSi^(4+)` `Na^+gtMg^(2+)ltAl^(3+)ltSi^(4+)`, `Na^+ltMg^(2+)gtAl^(3+)gtSi^(4+)`

A

'Na^+ltMg^(2+)ltAl^(3+)ltSi^(4+)'

B

Na^+gtMg^(2+)gtAl^(3+)gtSi^(4+)'

C

Na^+gtMg^(2+)ltAl^(3+)ltSi^(4+)'

D

Na^+ltMg^(2+)gtAl^(3+)gtSi^4,+'

Text Solution

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The correct Answer is:
B
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